Organic Chemistry / Core reactions
Acetals, imines and enamines
Addition of water, alcohols and amines to aldehydes and ketones: hydrates, hemiacetals, acetals, imines and enamines.
A-LevelUndergradIn a nutshell
Aldehydes and ketones react not only with strong nucleophiles but also with weak ones such as water, alcohols and amines. These additions are reversible, so which product you end up with depends on the conditions. Water gives hydrates; one alcohol molecule gives a hemiacetal, and two give an acetal, which is stable to base and so is often used to hide a carbonyl group during a synthesis. Amines give imines, which contain a C=N double bond, or, with secondary amines, enamines. These reactions are everywhere in biology. Glucose spends most of its time as a ring because its own OH group forms a cyclic hemiacetal with its aldehyde, and the light-sensitive pigment in your eye works because retinal is joined to a protein as an imine.
Reversible addition of weak nucleophiles
Water, alcohols and amines are weak nucleophiles, so their additions to C=O are reversible and usually need acid or base catalysis. Acid helps by protonating the carbonyl oxygen, which makes the carbon much more electrophilic.
Hydrates
Water adds to give a 1,1-diol (a hydrate, or gem-diol). Most hydrates cannot be isolated, but methanal in water is almost entirely hydrated, while propanone is barely hydrated at all. The more electrophilic and less hindered the carbonyl, the further the equilibrium lies towards the hydrate.
Hemiacetals and acetals
One molecule of alcohol adds to give a hemiacetal (an OH and an OR on the same carbon). With an acid catalyst and more alcohol, the OH is replaced by a second OR group, giving an acetal and water:
Removing the water drives the reaction forward; adding aqueous acid reverses it. Acetals are unaffected by bases, nucleophiles and reducing agents, which makes them useful protecting groups. The older terms hemiketal and ketal are still used for the products from ketones.
Sugars as cyclic hemiacetals
In glucose, the OH on C5 adds to the aldehyde at C1, forming a six-membered ring. The new OH on C1 can point down (\alpha) or up (\beta). The glycosidic bonds that link sugars into starch and cellulose are acetal linkages.
Imines
A primary amine adds to a carbonyl and then water is lost, giving an imine with a C=N bond:
Imine formation is fastest in weakly acidic solution, around pH 4–5. The orange precipitate formed between carbonyl compounds and 2,4-dinitrophenylhydrazine is a related condensation product (a hydrazone).
Thermodynamics of hydration
K_{\text{hyd}} reflects the stability of the carbonyl relative to the tetrahedral adduct. Electron-withdrawing substituents (CCl_3, CF_3) and ring strain (cyclopropanone) destabilise C=O and favour hydrates; alkyl and aryl groups (donation, conjugation, steric compression on sp^3) disfavour them. Exchange of ^{18}O from H_2^{18}O into a ketone reveals rapid, reversible hydration even when K_{\text{hyd}} is tiny.
Acetal formation: mechanism
1. Protonation of C=O, attack by ROH, deprotonation: hemiacetal. 2. Protonation of the hemiacetal OH, loss of water assisted by the lone pair on OR to give an oxocarbenium ion. 3. Attack by a second ROH and deprotonation: acetal.
Every step is reversible; the oxocarbenium ion is the key intermediate in both formation and hydrolysis. Acetal formation is entropically disfavoured (three molecules to two), so cyclic acetals from ethane-1,2-diol are preferred: the intramolecular second step is favoured, and water is removed with a Dean–Stark trap or a dehydrating agent such as trimethyl orthoformate. Acetals need acid to form and to hydrolyse, which is why they survive Grignard reagents, LiAlH_4 and base.
Worked example: to reduce the ester in ethyl 4-oxopentanoate with LiAlH_4 while keeping the ketone, protect the ketone as its ethane-1,2-diol acetal, reduce, then hydrolyse with aqueous acid to give 5-hydroxypentan-2-one.
Imines and the pH-rate profile
Primary amines add to give a carbinolamine (hemiaminal); acid-catalysed loss of water gives an iminium ion, then the imine. The rate is maximal at about pH 4–5: too acidic and the amine is protonated and non-nucleophilic; too basic and the carbinolamine OH is not protonated, so dehydration is slow. Related condensations with hydroxylamine (oximes), hydrazines (hydrazones) and semicarbazide (semicarbazones) give stable, often crystalline products.
Reductive amination reduces the imine or iminium in situ with NaBH_3CN or NaBH(OAc)_3, which react faster with C=N^+ than with C=O, making this a leading method for synthesising amines.
Enamines
Secondary amines (pyrrolidine, morpholine) give iminium ions that cannot lose an N–H proton, so they lose an \alpha-C–H instead, forming an enamine. Enamines are neutral enolate equivalents: the nitrogen lone pair makes the \alpha-carbon nucleophilic. In the Stork enamine synthesis they are alkylated with reactive halides or added to Michael acceptors, then hydrolysed to the substituted carbonyl. Organocatalysis by proline and its derivatives runs on the same enamine chemistry.
Biology
Pyridoxal phosphate forms imines with amino acids during transamination, and retinal forms a protonated imine (Schiff base) with a lysine in rhodopsin. Glycosidases cleave acetal bonds via oxocarbenium-like transition states.
Key points
- Water, alcohols and amines add reversibly to aldehydes and ketones, usually with acid catalysis.
- One alcohol gives a hemiacetal; acid and a second alcohol give an acetal plus water.
- Acetals are stable to base, nucleophiles and hydride, and are removed with aqueous acid, so they protect carbonyl groups.
- Primary amines give imines (C=N); formation is fastest around pH 4–5.
- Secondary amines give enamines, which react as neutral enolate equivalents.
- Glucose rings are cyclic hemiacetals and glycosidic bonds are acetals.
Check yourself
5 questions
1What is formed when one molecule of methanol adds to ethanal?
A single alcohol addition gives a carbon bearing both OH and OCH_3, which is a hemiacetal.
2Why are acetals useful protecting groups for ketones during a reaction with LiAlH_4?
With no C=O and no acidic proton, acetals ignore hydride and organometallic reagents, then hydrolyse back to the ketone in acid.
3Why is imine formation slow both at pH 1 and at pH 10?
The reaction needs a free amine to add and acid to catalyse dehydration, so the rate peaks in mildly acidic solution.
4Cyclohexanone reacts with pyrrolidine and an acid catalyst with removal of water. What forms?
A secondary amine forms an iminium ion that cannot lose N–H, so it loses an \alpha-proton to give an enamine.
5Why is acetal formation with ethane-1,2-diol more favourable than with two molecules of methanol?
Two molecules (ketone and diol) give two (acetal and water), avoiding the unfavourable entropy of combining three molecules into two.
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Recent preprints on this topic
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Matched by keyword from ChemRxiv via Crossref. Not peer-reviewed; read critically.